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# If the events A and B are independent ,then $P(A\cap B)$ is equal to

$\begin{array}{1 1}(A)\;P(A)+P(B)\quad(B)\;P(A)-P(B)\quad(C)\;P(A).P(B)\quad(D)\;P(A)|P(B)\end{array}$

Can you answer this question?

Toolbox:
• $p(A\;\cap\;B)=P(A).\;P(B)$
$'c'\; option\; is\; correct$

answered Feb 22, 2013
edited Mar 15, 2013