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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Current Electricity

Shown in the figure below is a meter-bridge setup with null deflection in the galvanometer.The value of the unknown resistor $R$ is

 

$\begin {array} {1 1} (A)\;13.75\Omega & \quad (B)\;220\Omega \\ (C)\;110\Omega & \quad (D)\;55\Omega \end {array}$

 

1 Answer

$ \large\frac{55}{20} $ $\large\frac{R}{80}$ $ \Rightarrow R = \large\frac{55 \times 8}{2}$ $220\Omega$
Ans : (B)
answered Feb 14, 2014 by thanvigandhi_1
edited Mar 14, 2014 by thanvigandhi_1
Where did that 80 come from? :-/
 

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