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# Shown in the figure below is a meter-bridge setup with null deflection in the galvanometer.The value of the unknown resistor $R$ is

$\begin {array} {1 1} (A)\;13.75\Omega & \quad (B)\;220\Omega \\ (C)\;110\Omega & \quad (D)\;55\Omega \end {array}$

Can you answer this question?

$\large\frac{55}{20}$ $\large\frac{R}{80}$ $\Rightarrow R = \large\frac{55 \times 8}{2}$ $220\Omega$
Ans : (B)
answered Feb 14, 2014
edited Mar 14, 2014

+1 vote