logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Chemistry  >>  Solutions
0 votes

1000 mL of aqueous solutions of $CaCO_3$ contains 1 gm of carbonate,concentration of the solution is

$\begin{array}{1 1}(a)\;10ppm\\(b)\;100ppm\\(c)\;1000ppm\\(d)\;10000ppm\end{array}$

Can you answer this question?
 
 

1 Answer

0 votes
Answer: 1000 ppm
Mass by volume percentage and parts per million are both and expression of concentration of a solution.
We are given Volume $= 1000\;mL$ and Mass $ = 1\;mg$.
$\Rightarrow ppm = \large\frac{\text{Mass}}{\text{volume}}$$ = \large\frac{1\; gm}{1000\; mL}$$ = \large\frac{1000 \; mg}{1\;L}$$ = 1000 \; ppm$
answered Feb 14, 2014 by sreemathi.v
edited Jul 15, 2014 by balaji.thirumalai
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...