Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A 4:1 molar mixture of He and $CH_4$ is contained in a vessel at 20 bar pressure. Due to a hole in the vessel, the gas mixture leaks out. What is the composition of the mixture effusing out initially?


Can you answer this question?

1 Answer

0 votes
Molar ratio of He and $CH_4$ is 4:1
Partial pressure ratio of He and $CH_4$ is 16:4
$\large\frac{n_{He}}{n_{CH_4}} = \sqrt{\large\frac{M_{CH_4}}{M_{He}}}\times\large\frac{P_{He}}{P_{CH_4}}$
Since total pressure = 20 bar
$= \sqrt{\large\frac{16}{4}}\times\large\frac{16}{4}$
Since time of diffusion for both is same
= 8:1
The composition of mixture initially gone out for He and $CH_4$ is 8:1
Hence answer is (c)
answered Feb 15, 2014 by sharmaaparna1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App