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A bag contains 5 red and 3 blue balls.If 3 balls are drawn at random without replacement the probability of getting exactly one red ball is

1 Answer

\(P(R\;B\;B)\;=\Large\frac{5}{8}\;x\;\frac{3}{7}x\frac{2}{6}\;=\frac{5}{56}\)
\(P(B\;R\;B)\;=\;\Large\frac{3}{8}\;x\;\frac{5}{7}\;x\;\frac{2}{6}\;=\;\frac{5}{56}\)
\(P(B\;B\;R)\;=\;\Large\frac{3}{8}\;x\;\frac{2}{7}\;x\;\frac{5}{7}\;=\;\frac{5}{56}\)
\((Exactly 1 Red)\;=\;\Large\frac{5}{56}\;+\;\frac{5}{56}\;+\;\frac{5}{56}\)
=\(\Large\frac{15}{56}\)
'C' option is correct

 

answered Feb 22, 2013 by poojasapani_1
edited Mar 15, 2013 by poojasapani_1
 

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