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A bag contains 5 red and 3 blue balls.If 3 balls are drawn at random without replacement the probability of getting exactly one red ball is

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\((Exactly 1 Red)\;=\;\Large\frac{5}{56}\;+\;\frac{5}{56}\;+\;\frac{5}{56}\)
'C' option is correct


answered Feb 22, 2013 by poojasapani_1
edited Mar 15, 2013 by poojasapani_1

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