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A container having 3 mole of gas occupies 60 litre at pressure P and temperature T . If 0.2 mole of gas are introduced at same P and T. Find the change in volume.

$(a)\;10\;litre\qquad(b)\;4\;litre\qquad(c)\;5\;litre\qquad(d)\;6\;litre$

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Given
V = kn
v = 60 litre
n = 3 mole
$\therefore k = \large\frac{60}{3}$
$\;\;\;\;\;=20$
Since $\bigtriangleup v = k.\bigtriangleup n$
$\Rightarrow = 20\times0.2$
$\Rightarrow = 4 litre$
Hence answer is (b)
answered Feb 15, 2014 by sharmaaparna1
 

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