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A moving coil galvanometer has 150 equal divisions. Its current sensitivity is 10 divisions per milliampere and voltage sensitivity is 2 divisions per millivolt. In order that each division reads 1 volt, the resistance in ohms needed to be connected in series with the coil will be

$\begin {array} {1 1} (A)\;10^3 & \quad (B)\;10^5 \\ (C)\;99995 & \quad (D)\;9995 \end {array}$


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$I_g=15mA\: \: \: \: \:Vg=75mV$
$R = \large\frac{V}{I_g}$ $- \large\frac{V_g}{I_g}$
Ans : (D)
answered Feb 15, 2014 by thanvigandhi_1
edited Mar 14, 2014 by thanvigandhi_1

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