# A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be

$\begin {array} {1 1} (A)\;Doubled & \quad (B)\;Four\: times \\ (C)\;One\: fourth & \quad (D)\;Halved \end {array}$

## 1 Answer

$H = \large\frac{V^2\Delta t}{R}$
$H' = \large\frac{V^2}{R'}$$\Delta t$
Given $R' = \large\frac{R}{2}$
Ans : (A)
answered Feb 15, 2014
edited Mar 14, 2014

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