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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Current Electricity
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An energy source will supply a constant current into the loads of its internal resistance is

$\begin {array} {1 1} (A)\;equal\:  to\:  the\:  resistance\:  of\:  the\:  load \\ (B)\;very\:  large\:  as\:  compared \: to \: the\:  load \: resistance \\ (C)\;zero \\ (D)\;non-zero\:  but\:  less\:  than\:  the\:  resistance\:  of\:  the\:  load \end {array}$


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$ I = \large\frac{E}{R+r} \sim \large\frac{E}{r}$
Ans : (B)
answered Feb 15, 2014 by thanvigandhi_1
edited Mar 14, 2014 by thanvigandhi_1

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