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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Current Electricity
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The resistance of a bulb filament is $ 100\Omega$ at a temperature of $100^{\circ}C$. If its temperature coefficient of resistance be $0.005 \: per^{\circ}C$ its resistance will become $200\Omega$ at a temperature of

$\begin {array} {1 1} (A)\;200^{\circ}C & \quad (B)\;300^{\circ}C \\ (C)\;400^{\circ}C & \quad (D)\;500^{\circ}C \end {array}$


Can you answer this question?

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$200=100[1+(0.005 \times \Delta t)]$
$ T-100=200$
Ans : (B)
answered Feb 15, 2014 by thanvigandhi_1
edited Mar 14, 2014 by thanvigandhi_1

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