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States of Matter: Liquids and Gases
5.6 litre of an unknown gas at NTP requires 12.5 calorie to raise its temperature by $10^{\large\circ}C$ at constant volume. Calculate the $C_v$ of the gas.
$(a)\;3\;calorie\qquad(b)\;5\;calorie\qquad(c)\;7\;calorie\qquad(d)\;9\;calorie$
jeemain
chemistry
physical-chemistry
class11
unit5
states-of-matter
ideal-gas-equation
easy
q43
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asked
Feb 16, 2014
by
sharmaaparna1
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Sep 16, 2014
by
sharmaaparna1
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1 Answer
Given
Volume = 5.6 litre
R = 0.0821
T = 273K
We have $n = \large\frac{PV}{RT}$
$=\large\frac{1\times5.6}{0.0821\times273}$
= 0.25
Also $q = mS\bigtriangleup T$
$12.5 = 0.25\times C_v\times10$
$C_v = 5\;calorie$
Hence answer is (b)
answered
Feb 16, 2014
by
sharmaaparna1
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