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A battery is used to charge a parallel plate capacitor till the potential difference between the plates becomes equal to the electromotive force of the battery. The ratio of the energy stored in the capacitor and the work done by the battery will be

$\begin {array} {1 1} (A)\;\large\frac{1}{4} & \quad (B)\;\large\frac{1}{2} \\ (C)\;1 & \quad (D)\;2 \end {array}$


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Energy stored in capacitor is $\large\frac{qV}{2}$
Work done by battery is $qV.$
Ans : (B)
answered Feb 16, 2014 by thanvigandhi_1
edited Mar 14, 2014 by thanvigandhi_1

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