# An ideal coil of $10H$ is connected in series with a resistance of $5 \Omega$ and a battery of $5V$. 2 second after the connection is made the current flowing in amperes in the circuit is

$\begin {array} {1 1} (A)\;1-e & \quad (B)\;e \\ (C)\;e^{-1} & \quad (D)\;1-e^{-1} \end {array}$

$I = I_0 (1 – e^{\large\frac{Rt}{L}}) = 1 – e^{-1}$
Ans : (D)
edited Mar 14, 2014