$\begin {array} {1 1} (A)\;3 & \quad (B)\;\large\frac{1}{3} \\ (C)\;\large\frac{8}{9} & \quad (D)\;2 \end {array}$

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$ \large\frac{I_1}{I_2} $ $ = \large\frac{R_2}{R_1} $

[ Current divider rule since voltage is same in parallel ]

$ \large\frac{I_1}{I_2} $ $ = \large\frac{L_2}{L_1} $ $ \times \large\frac{r_1^2}{r_2^2}$

$ \therefore \large\frac{I_1}{I_2} $ $= \large\frac{3}{4} $ $ \times \bigg( \large\frac{2}{3} \bigg)^2$ $ = \large\frac{1}{3}$

Ans : (B)

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