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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Current Electricity
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An electric current is passed through a circuit containing two wires of the same material, connected in parallel. If the length and radii of the wires are in the ratio of $ \large\frac{4}{3} \: and \:\large\frac{2}{3}$, then the ratio of the currents passing through the wires will be

$\begin {array} {1 1} (A)\;3 & \quad (B)\;\large\frac{1}{3} \\ (C)\;\large\frac{8}{9} & \quad (D)\;2 \end {array}$

 

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1 Answer

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$ \large\frac{I_1}{I_2} $ $ = \large\frac{R_2}{R_1} $
[ Current divider rule since voltage is same in parallel ]
$ \large\frac{I_1}{I_2} $ $ = \large\frac{L_2}{L_1} $ $ \times \large\frac{r_1^2}{r_2^2}$
$ \therefore \large\frac{I_1}{I_2} $ $= \large\frac{3}{4} $ $ \times \bigg( \large\frac{2}{3} \bigg)^2$ $ = \large\frac{1}{3}$
Ans : (B)

 

answered Feb 16, 2014 by thanvigandhi_1
edited Mar 14, 2014 by thanvigandhi_1
 

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