$\begin{array}{1 1}(A)\;\large\frac{3}{28}\\(B)\;\large\frac{2}{21}\\(C)\;\large\frac{1}{28}\\(D)\;\large\frac{167}{168}\end{array} $

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- three ball drawn from 3O,3G,2B balls without replacement
- we can get 2 Green and 1Blue in the following ways
- (G G B) (G B G) (B G G)

p(G G B) =\(\frac{3}{8}\)X\(\frac{2}{7}\)X\(\frac{2}{6}\)

p(G B G)=\(\frac{3}{8}\)X\(\frac{2}{7}\)X\(\frac{2}{6}\)

p(B G G )=\(\frac{2}{8}\)X\(\frac{3}{7}\)X\(\frac{2}{6}\)

p(getting 2Green and 1 Blue)

=\(\frac{9}{84}\)=\(\frac{3}{28}\) ,A, option is correctAsk Question

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