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# A box contains 3 orange balls,3 green balls and blue balls.three balls are drawn at random from the box without replacement .The probability of drawing 2 green balls and one blue ball is

\$\begin{array}{1 1}(A)\;\large\frac{3}{28}\$B)\;\large\frac{2}{21}\\(C)\;\large\frac{1}{28}\\(D)\;\large\frac{167}{168}\end{array}  Can you answer this question? ## 1 Answer 0 votes Toolbox: • three ball drawn from 3O,3G,2B balls without replacement • we can get 2 Green and 1Blue in the following ways • (G G B) (G B G) (B G G) p(G G B) =\(\frac{3}{8}$X$\frac{2}{7}$X$\frac{2}{6}$
p(G B G)=$\frac{3}{8}$X$\frac{2}{7}$X$\frac{2}{6}$
p(B G G )=$\frac{2}{8}$X$\frac{3}{7}$X$\frac{2}{6}$
p(getting 2Green and 1 Blue)
=$\frac{9}{84}$=$\frac{3}{28}$      ,A, option is correct
edited Feb 20, 2013