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A current of 2A when passed for five hour through a molten metal salt,it deposits 22.2g of metal of atomic weight 177.The oxidation state of metal in metal salt is

$\begin{array}{1 1}(a)\;+1&(b)\;+2\\(c)\;+3&(d)\;+4\end{array}$

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Weight=$\large\frac{Eit}{F}=\frac{Mit}{n\;factor}$
$22.2=\large\frac{177\times 5\times 2\times 60\times 60}{n\times 96500}$
$n=2.97\approx 3$
So oxidation state of metal will be 3
Hence (c) is the correct answer.
answered Feb 17, 2014 by sreemathi.v
 

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