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If $E^0_{Fe^{+2}/Fe}$ is $X_1$,$E^0_{Fe^{+3}/Fe}$ is $X_2$ then $E^0_{Fe^{+3}/Fe^{+2}}$ will be

$\begin{array}{1 1}(a)\;3X_2-2X_1\\(b)\;X_2-X_1\\(c)\;X_2+X_1\\(d)\;2X_1+3X_2\end{array}$

1 Answer

$\Delta G_3=\Delta G_2-\Delta G_1$
$-n_3FE_3^0=-n_2FE_2^0+n_1FE_1^0$
$E_3^0=\large\frac{n_2E^0_2-n_1E_1^0}{n_3}$
$\Rightarrow 3X_2-2X_1$
Hence (a) is the correct answer.
answered Feb 17, 2014 by sreemathi.v
 

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