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Sulphur Vapour($S_n$) diffuses through a process plug at 0.354 rate of diffusion of $O_2$ gas under similar conditions of P and T. Find the volume of n.


1 Answer

$\large\frac{r_{sn}}{r_{o_2}} = \sqrt{\large\frac{M_{O_2}}{M_{Sn}}}$
$\Rightarrow 0.354 = \sqrt{\large\frac{32}{M_{Sn}}}$
$\therefore M_{Sn} = 255.38$
or $n\times32 = 255.38 $
$n = \large\frac{255.38}{32}$
$\Rightarrow n = 8$
Hence answer is (b)
answered Feb 17, 2014 by sharmaaparna1

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