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How many unit cells are present in a cubic shaped ideal crystals of NaCl of mass 1.0g?

$\begin{array}{1,1}(a)\;1.28\times10^{21} unit\;cells\\(b)\;1.71\times10^{21} unit\;cells\\(c)\;2.57\times10^{21} unit\;cells\\(d)\;5.14\times10^{21} unit\;cells \end {array}$

1 Answer

n = 4 for f.c.c
No of atoms in 1gram NaCl = $\large\frac{6.023\times10^{23}}{58.5\times4}$
$=2.57\times10^{21}$ unit cells
Hence the answer is (c)
answered Feb 17, 2014 by sharmaaparna1

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