$\begin{array}{1 1}(A)\;\frac{1}{256}\quad(B)\;\frac{7}{32}\quad(C)\;\frac{5}{32}\quad(D)\;\frac{3}{32}\end{array} $

- probability of getting head in a toss p=\(\Large\frac{1}{2}\)
- q=1-\(\Large\frac{1}{2}\)=\(\Large\frac{1}{2}\)
- 8 coins are tossed n=8
- \(p(X=r)=c^n_r\;p^r\;q^{n-r}\)

\(\Large\;n=8\; r=3\)

\(\Large\frac{8\times7\times6}{1\times2\times3}\)\(\times\)\(\Large\frac{1}{28}\)

\(\Large56\times\frac{1}{28}\)

\(\Large\frac{7}{32}\)

'b'option is correct

Ask Question

Tag:MathPhyChemBioOther

Take Test

...