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In a compound atoms of element Y form ccp lattice and those of element X occupy ${\large\frac{2}{3}}^{rd}$ of tetrahedral voids. The formula of the compound will be


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  • Let, the number of close packed spheres be N,
    The number of octahedral voids generated = N
    The number of tetrahedral voids generated = 2N
Number of atoms of Y = N = 4
Number of atoms of X = $\large\frac{2}{3}\times 2N = \large\frac{2}{3}\times 8= \large\frac{16}{3}$
$\therefore$ Formula of the compound will be $X_4Y_3$
Hence answer is (a)
answered Feb 17, 2014 by sharmaaparna1
edited Apr 2, 2014 by mosymeow_1
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