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# The EMF of cell $Ag/AgCl(K_{sp})(saturated\; sol)\parallel Cl^-(C_1)/AgCl(K_{sp}/Ag)$ is given by

$\begin{array}{1 1}(a)\;E=-\large\frac{0.059}{1}\normalsize\log \large\frac{\sqrt{K_{sp}}}{C_1}\\(b)\;E=-\large\frac{0.059}{1}\normalsize\log \large\frac{C_1}{\sqrt{K_{sp}}}\\(c)\;E=-\large\frac{0.059}{1}\normalsize\log \large\frac{\sqrt{K_{sp}}}{C_1^2}\\(d)\;E=\large\frac{0.059}{1}\normalsize\log \large\frac{C_1}{\sqrt{K_{sp}}}\end{array}$

Can you answer this question?