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Copper Crystallizes in f.c.c with a unit cell length of 361 pm. What is the radius of copper atom?

$(a)\;108\;pm\qquad(b)\;127\;pm\qquad(c)\;157\;pm\qquad(d)\;181\;pm$

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For f.c.c structure
Radius of the atom = $\large\frac{a}{2\sqrt2}$
$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\; = \large\frac{361}{2\sqrt2}$
$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\; = 127.56$
Hence answer is (b)
answered Feb 17, 2014 by sharmaaparna1
 

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