The EMF of cell is : $Pt/H_2/CH_3COOH(0.1M)\parallel NH_4OH(0.01M)/H_2/Pt$.$K_a$ for $CH_3COOH=1.8\times 10^{-5}$ and $K_b$ for $NH_4OH=1.8\times 10^{-5}$

Question

$\begin{array}{1 1}(a)\;0.4V\\(b)\;0.35V\\(c)\;0.45V\\(d)\;0.3V\end{array}$