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Home  >>  CBSE XI  >>  Math  >>  Sequences and Series
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Find the first 5 terms of the sequence whose $n^{th}$ term is given by $t_n=\large\frac{n}{n+1}$

$\begin{array}{1 1}\large \frac{1}{2}, \frac{2}{3}, \frac{3}{4}, \frac{4}{5}, \frac{5}{6} \\\large \frac{1}{3}, \frac{3}{5}, \frac{5}{7}, \frac{7}{9}, \frac{9}{11} \\ \large \frac{1}{3}, \frac{3}{4}, \frac{4}{5}, \frac{5}{6}, \frac{6}{7} \\0, \large \frac{1}{2}, \frac{2}{3}, \frac{3}{4}, \frac{4}{5} \end{array} $

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Given: $t_n=\large\frac{n}{n+1}$
By putting $n=1,2.....$ in $t_n$ we can get the first 5 terms as
$t_1=\large\frac{1}{1+1}=\frac{1}{2}$
$t_2=\large\frac{2}{2+1}=\frac{2}{3}$
$t_3=\large\frac{3}{3+1}=\frac{3}{4}$
$t_4=\large\frac{4}{4+1}=\frac{4}{5}$
$t_5=\large\frac{5}{5+1}=\frac{5}{6}$
answered Feb 17, 2014 by rvidyagovindarajan_1
 

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