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Home  >>  CBSE XI  >>  Math  >>  Sequences and Series
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Find the first $5$ terms of the sequence whose $n^{th}$ term is given by $t_n=2^n$

$\begin{array}{1 1} 2,4,8,16,32 \\ 2,4,6,8,10 \\ 2,4,12,24,48 \\ 2,4,8,32,64 \end{array} $

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Given: $t_n=2^n$
By putting $n=1,2,3......$ we can get the first 5 terms as
$t_1=2^1=2$
$t_2=2^2=4$
$t_3=2^3=8$
$t_4=2^4=16$
$t_5=2^5=32$
answered Feb 17, 2014 by rvidyagovindarajan_1
 

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