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Home  >>  JEEMAIN and NEET  >>  Chemistry  >>  Electrochemistry

In an electrolysis experiment electric current was passed for 5hr through two cells connected in series.The first cell contains gold salt and second contains $CuSO_4$ solution.9.83g of gold was deposited in first cell.If the oxidation number of Au is +3,find the amount of copper deposited in second cell

$\begin{array}{1 1}(a)\;4g&(b)\;5g\\(c)\;4.7g&(d)\;5.7g\end{array}$

1 Answer

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At weight of gold is 197.
Eq.wt of gold =$\large\frac{At.wt}{\text{Oxidation number}}=\frac{197}{3}$
$\Rightarrow 65.66$
As we know that
Hence (c) is the correct answer.
answered Feb 17, 2014 by sreemathi.v

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