Email
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

In an electrolysis experiment electric current was passed for 5hr through two cells connected in series.The first cell contains gold salt and second contains $CuSO_4$ solution.9.83g of gold was deposited in first cell.The magnitude of current in amperes is :-

$\begin{array}{1 1}(a)\;0.7amp&(b)\;0.8amp\\(c)\;0.6amp&(d)\;0.5amp\end{array}$

1 Answer

Comment
A)
$W=Z\times i\times t=\large\frac{E}{96500} $$i\times t$
$4.7=\large\frac{\Large\frac{63.5}{2}}{96500}\times$$ 1\times 5\times 60\times 60$
$\therefore i=\large\frac{4.75\times 96500\times 2}{5\times 60}$
$\Rightarrow 0.8amp$
Hence (b) is the correct answer.
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
...