Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

An electric current is passed through two electrolytic cells connected in series.One containing a solution of silver nitrate and the other solution of $H_2SO_4$.What volume of oxygen measured at $25^{\large\circ}C$ and 750mm of Hg would be liberated from $H_2SO_4$ if 1mole and of $Ag^+$ are deposited from silver nitrate solution?

$\begin{array}{1 1}(a)\;4.2l&(b)\;6.2l\\(c)\;5.3l&(d)\;3.2l\end{array}$

Can you answer this question?

1 Answer

0 votes
1 mole of $Ag^+$=1 equivalent of $Ag^+$
$\therefore$ Equivalent of $O_2=\large\frac{22.4}{4}$$=5.6litres$ of NTP
$\therefore \large\frac{P_1\times V_1}{T_1}= \large\frac{P_2\times V_2}{T_2}$
$\large\frac{750\times V_1}{298}=\frac{760\times 5.6}{273}$
$\therefore V_1$(volume of oxygen at $25^{\large\circ}C$ and 750mm)=$\large\frac{760\times 5.6\times 298}{273\times 750}$
$\Rightarrow 6.2litres$
Hence (b) is the correct answer.
answered Feb 17, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App