# Find the first 5 terms of the series whose general term is given by $t_n=\large\frac{2n-3}{6}$
$\begin{array}{1 1}\large \frac{1}{6}, \frac{1}{2}, \frac{5}{6}, \frac{7}{6} \frac{12}{6} \\\large \frac{1}{6}, \frac{1}{2}, \frac{5}{6}, \frac{7}{6} \frac{9}{6} \\ \large\frac{-1}{6}, \frac{1}{6}, \frac{4}{6}, \frac{5}{6}, \frac{7}{6} \\\large\frac{-1}{6}, \frac{1}{6}, \frac{1}{2}, \frac{5}{6}, \frac{7}{6} \end{array}$