# Find $a_{17},\:a_{24}$ if $a_n=4n-3$

$\begin{array}{1 1}a_{17}=65,\:\:a_{24}=93 \\a_{17}=35,\:\:a_{24}=63 \\ a_{17}=25,\:\:a_{24}=93 \\a_{17}=65,\:\:a_{24}=83 \end{array}$

Given: General term of a sequence, $a_n=4n-3$
By putting $n=17$ we get the $17^{th}$ term = $a_{17}=4\times 17-3$
$i.e.,\:\:a_{17}=68-3=65$
Similarly by putting $n=24$ , we get $a_{24}=4\times24-3=96-3=93$
$a_{17}=65,\:\:a_{24}=93$