Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
+1 vote

How many number of atoms are there in a cube based unit cell having one atom each corner and two atoms on each body diagonal of cube ?


Can you answer this question?

1 Answer

0 votes
There are four body diagonals and atoms on the body diagonal are not shared by any other unit cell.
$\therefore$ Atoms at the corner = $8\times \large\frac{1}{8}$
$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\; = 1$
Atoms on the body diagonal = $2\times4$
$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\; =8$
$\therefore$ Total number of atoms = 1+8 = 9
Hence answer is (a)
answered Feb 18, 2014 by sharmaaparna1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App