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If the radius of $Cs^+$ is 169pm and that of $Cl^-$ is 181pm then find the co-ordination number of $Cs^+$


1 Answer

$\large\frac{r^+}{r^-} = \large\frac{169}{181}$
Since radius ratio > 0.732
$\therefore$ CsCl crystallizes in b.c.c lattice with co-ordination number of $Cs^+$ = 8
Hence answer is (b)
answered Feb 18, 2014 by sharmaaparna1

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