Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Calculate EMF of concentration cell consisting of zinc electrodes,one immersed in a solution of 0.01M $Zn^{+2}$ ions and the other in a solution of 0.1M $Zn^{+2}$ ions at $25^{\large\circ}C$.The two solution are separated by a salt bridge

$\begin{array}{1 1}(a)\;0.03V\\(b)\;0.09V\\(c)\;1.2V\\(d)\;-0.03V\end{array}$

Can you answer this question?

1 Answer

0 votes
The cell may be represented as $Zn/Zn^{+2}(0.01M)\parallel Zn^{+2}(0.1M)/Zn$
The EMF of cell is given by
$E_{cell}=\large\frac{RT}{nF}$$ln \large\frac{C_2}{C_1}$
$\Rightarrow \large\frac{0.0591}{2}$$\log \large\frac{0.1}{0.01}$
$\Rightarrow 0.03$V
Hence (a) is the correct answer.
answered Feb 18, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App