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Find $a_7$ if $a_n=\large\frac{n^2}{2^{n}}$

$\begin{array}{1 1}\large\frac{49}{128} \\ \large\frac{81}{128} \\ \large\frac{64}{128} \\ \large\frac{36}{128} \end{array} $

1 Answer

Given: $a_n=\large\frac{n^2}{2^n}$
By putting $n=7$ we get the $7^{th}$ term as
$a_7=\large\frac{7^2}{2^7}=\frac{49}{128}$
answered Feb 18, 2014 by rvidyagovindarajan_1
 
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