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Home  >>  CBSE XI  >>  Math  >>  Sequences and Series

Find $a_9$ if $a_n=(-1)^{n-1}.n^3$

$\begin{array}{1 1}729 \\ 719 \\ 814 \\ 709 \end{array} $

1 Answer

Given: $a_n=(-1)^{n-1}.n^3$
By putting $n=9$ we get the $9^{th}$ term as
$a_9=(-1)^8.9^3=729$
answered Feb 18, 2014 by rvidyagovindarajan_1
 
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