logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  CBSE XI  >>  Math  >>  Sequences and Series
0 votes

Find $a_9$ if $a_n=(-1)^{n-1}.n^3$

$\begin{array}{1 1}729 \\ 719 \\ 814 \\ 709 \end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
Given: $a_n=(-1)^{n-1}.n^3$
By putting $n=9$ we get the $9^{th}$ term as
$a_9=(-1)^8.9^3=729$
answered Feb 18, 2014 by rvidyagovindarajan_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...