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Find $a_9$ if $a_n=(-1)^{n-1}.n^3$

$\begin{array}{1 1}729 \\ 719 \\ 814 \\ 709 \end{array} $

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Given: $a_n=(-1)^{n-1}.n^3$
By putting $n=9$ we get the $9^{th}$ term as
answered Feb 18, 2014 by rvidyagovindarajan_1

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