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Find $a_{20}$ if $a_n=\large\frac{n(n-2)}{n+3}$

$\begin{array}{1 1}\frac{360}{23} \\ \frac{240}{23} \\ \frac{380}{23} \\ \frac{420}{23} \end{array} $

1 Answer

$a_n=\large\frac{n(n-2)}{n+3}$
By putting $n=20$ we get the $20^{th}$ term as
$a_{20}=\large\frac{20(20-2)}{20+3}=\frac{360}{23}$
answered Feb 18, 2014 by rvidyagovindarajan_1
 
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