logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  CBSE XI  >>  Math  >>  Sequences and Series
0 votes

Find $a_{20}$ if $a_n=\large\frac{n(n-2)}{n+3}$

$\begin{array}{1 1}\frac{360}{23} \\ \frac{240}{23} \\ \frac{380}{23} \\ \frac{420}{23} \end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
$a_n=\large\frac{n(n-2)}{n+3}$
By putting $n=20$ we get the $20^{th}$ term as
$a_{20}=\large\frac{20(20-2)}{20+3}=\frac{360}{23}$
answered Feb 18, 2014 by rvidyagovindarajan_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...