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A ray of light passes through four transparent media with refractive indices $\mu_1,\mu_2,\mu_3$ of all media are parallel, If the emergent ray CD is parallel ti incident ray AB. We must have


$(a)\;\mu_1 = \mu_2 \\ (b)\;\mu_2=\mu_3 \\ (c)\;\mu_3=\mu_4 \\ (d)\;\mu_4 =\mu_1 $

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According to Snell's law,
$\mu \sin \theta= constant$
Since the emergent ray is parallel to the incident ,the emergent angle = incident angle
Which gives, $\mu_1=\mu_4$
Hence d is the correct answer.


answered Feb 18, 2014 by meena.p
edited Jul 23, 2014 by thagee.vedartham

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