# A lens of focal length f projects m times magnified image of an object on a screen.The distance of screen from lens is

$(a)\;\frac{f}{m-1} \\ (b)\;f(m-1) \\ (c)\;\frac{f}{m+1} \\ (d)\;f(m+1)$

Image will be real.
we know that
$\large\frac{1}{f} =\frac{1}{v} -\frac{1}{u}$
$\large\frac{v}{f}$$=1-\large\frac{v}{u} => \large\frac{v}{f}$$ =1+m$
$v= f(m+1)$
Hence d is the correct answer.