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A lens of focal length f projects m times magnified image of an object on a screen.The distance of screen from lens is

$(a)\;\frac{f}{m-1} \\ (b)\;f(m-1) \\ (c)\;\frac{f}{m+1} \\ (d)\;f(m+1) $

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Image will be real.
we know that
$\large\frac{1}{f} =\frac{1}{v} -\frac{1}{u}$
=> $\large\frac{v}{f}$$ =1+m $
$v= f(m+1)$
Hence d is the correct answer.
answered Feb 18, 2014 by meena.p

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