logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

Two lenses , One concave and the other convex of same power are placed such that their principal axes coincide. If the separation b/w the lenses is x, then ,

a) real image is formed for x=0 only.

(b) real image is formed for all values of x

(c) System will behave like a glass plate for x=0

(d) virtual image is formed for all values of x other than zero.

Can you answer this question?
 
 

1 Answer

0 votes
$\large\frac{1}{f}=\frac{1}{f_1} +\frac{1}{f_2}-\frac{x}{f_1f_2}$
$\large\frac{1}{f}=\frac{1}{f_1} -\frac{1}{f_1}+\frac{x}{f_1^2}$
$\large\frac{1}{f}=\frac{x}{f_1^2}$$ => f >0$ for every x
for $x=0,f =\infty$
Hence for $x=0$ system will behave like a glass plate.
Hence c is the correct answer.
answered Feb 19, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...