If $A$ and $B$ are independent events probability of occurance of $A$ and $B$
$p(A\cap B)=p(A)p(B/A)$ by multiplication theorem.
$p(B/A)$ is the probability of occurance of $B$
Given that $A$ has occured
But $p(B/A)=p(B) $ as $A$ and $B$ are independent.
There fore $p(A\cap B) =p(A) p(B)$
The given statement is 'True'.