logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

A ray of light falls on a transparent glass slab with refractive index (relative to air) of $1.62$ . The angle of incident for which the reflected and refractive rays are mutually perpendicular is :

$(a)\;\tan ^{-1} (1.62) \\ (b)\;\sin ^{-1} (1.62) \\ (c)\;\cos^{-1} (1.62) \\ (d)\;None\;of \;these $

Can you answer this question?
 
 

1 Answer

0 votes
We know that $\mu= \large\frac{\sin r}{\sin r}$ and $i+r=90^{\circ}$
or $ r=90^{\circ}-i$
$\mu= \large\frac{\sin i}{\sin (90-i)}$
$\qquad=\tan i$
or $i= \tan ^{-1} (\mu)$
$\qquad= \tan ^{-1}(1.62)$
Hence a is the correct answer.
answered Feb 19, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...