Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A uniform magnetic field $ \overrightarrow B = B_0\hat j$ exists in space. A particle of mass $m$ and charge $q$ is projected towards negative $x$-axis with speed $v$ from a point $(d,0,0)$. The maximum value of $v$ for which the particle does not hit the $y-z$ plane is

$\begin {array} {1 1} (a)\;\large\frac{2Bq}{dm} & \quad (b)\;\large\frac{Bqd}{m} \\ (c)\;\large\frac{Bq}{2dm} & \quad (d)\;\large\frac{Bqd}{2m} \end {array}$


Can you answer this question?

1 Answer

0 votes
As the magnetic field is uniform, the question requires the following condition to be satisfied
$d = \large\frac{mv}{qB}$
$ \Rightarrow v = \large\frac{Bqd}{m}$
Ans : (b)
answered Feb 19, 2014 by thanvigandhi_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App