info@clay6.com
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

Ratio of the magnetic field at the centre of a current carrying coil of radius $R$ and at a distance of $3R$ on its axis is

$\begin {array} {1 1} (a)\;10\sqrt{10} & \quad (b)\;20\sqrt{10} \\ (c)\;2\sqrt{10} & \quad (d)\;\sqrt{10} \end {array}$

 

1 Answer

Comment
A)
Need homework help? Click here.
The desired ratio is $ \Large\frac{\Large\frac{\mu_0i}{2R}}{\Large\frac{\mu_0iR^2}{2(R^2+9R^2)^{\Large\frac{3}{2}}}}$
Ans : (a)
Home Ask Homework Questions
...