+91-9566306857  (or)  +91-9176170648

Ask Questions, Get Answers


A charged particle enters a magnetic field at right angles to the magnetic field. The field exists for a length equal to 1.5 times the radius of the circular path of the particle. The particle will deviate from its path by

$\begin {array} {1 1} (a)\;90^{\circ} & \quad (b)\;Sin^{-1}\bigg(\large\frac{1}{3} \bigg) \\ (c)\;Sin^{-1}\bigg(\large\frac{2}{3} \bigg) & \quad (d)\;180^{\circ} \end {array}$


1 Answer

If the width of the region is greater than the radius of the circular path, the angle of deviation is always $180^{\circ}$
Ans : (d)
answered Feb 19, 2014 by thanvigandhi_1

Related questions