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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Magnetism and Matter
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Magnetic moment of an electron in the $n^{th}$ orbit of the hydrogen atom is

$\begin {array} {1 1} (a)\;neh/ \pi \: m & \quad (b)\;neh/4 \pi \: m \\ (c)\;meh/ \pi \: n & \quad (d)\;meh/4 \pi \: n \end {array}$


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$ \large\frac{Magnetic\: moment}{Angular\: momentum}$ $ = \large\frac{e}{2m}$
Angular Momentum = $ \large\frac{nh}{2 \pi}$
Ans : (b)
answered Feb 19, 2014 by thanvigandhi_1

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