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In the below reaction the product Y is

$\begin{array}{1 1} a \\ b \\ c \\ d \end{array}$

Can you answer this question?

1 Answer

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The formation of X involves the addition of $NH_2OH.The conversion of X to Y is the Beckmann rearrangement.The mechanism as shown below
Hence (c) is the correct answer.
answered Feb 19, 2014 by sreemathi.v
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