Email
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

A plane mirror is made of glass slab $(\mu g=1.5)\;2.5\;cm$ thick and silvered on back. A point objected is placed 5 cm in front of unsilvered face of mirror. What will be the position of final image.

(a)8.33 cm from unsilvered face

(b)14.6 cm from unsilvered face

(c) 12 cm from unsilvered face  

(d) 5.67 cm from unsilvered face 

1 Answer

Comment
A)
Let $I_1,I_2$ and $I_3$ be the image formed by
(i) refraction from ADC
(ii) reflection from BEF and
(iii) again refraction from ADC
Then $BI_1=5 \mu_g=5(1.5)=7.5 \;cm$
Now $\in I_1=(7.5 +2.5)=10 \;cm$
$\in I_2=10\;cm$ behind mirror.
Now $BI_2=(10+2.5) =12.5 \; cm$
$\therefore BI_3=\large\frac{12.5}{\mu g}=\frac{12.5}{1.5}$
$\qquad= 8.33 \;cm$
Hence a is the correct answer.

 

Thnk u so much !! Even i was confused in this concept!!
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
...