Comment
Share
Q)

# A plane mirror is made of glass slab $(\mu g=1.5)\;2.5\;cm$ thick and silvered on back. A point objected is placed 5 cm in front of unsilvered face of mirror. What will be the position of final image.

(a)8.33 cm from unsilvered face

(b)14.6 cm from unsilvered face

(c) 12 cm from unsilvered face

(d) 5.67 cm from unsilvered face

Comment
A)
Let $I_1,I_2$ and $I_3$ be the image formed by
Then $BI_1=5 \mu_g=5(1.5)=7.5 \;cm$
Now $\in I_1=(7.5 +2.5)=10 \;cm$
$\in I_2=10\;cm$ behind mirror.
Now $BI_2=(10+2.5) =12.5 \; cm$
$\therefore BI_3=\large\frac{12.5}{\mu g}=\frac{12.5}{1.5}$
$\qquad= 8.33 \;cm$