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Refer the below :

$\begin{array}{1 1}(a)\;CH_2=CH-CH_2\;and\;CH_3-CH_2-CH_2\\(b)\;CH=CH-CH_2\;and\;CH_2-CH_2-CH_2\\(c)\;CH_2=CH-CH_3\;and\;CH_3-CH_2-CH_3\\(d)\;\text{None of these}\end{array}$

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$N_2H_4/OH^-$ reduces only -CHO group to -$CH_3$ and Zn-HG/HCl(clemmensen's reduction) reduces both C=C and -CHO group.
Hence (c) is the correct option.
answered Feb 19, 2014 by sreemathi.v
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