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Haloform reaction may be depicted as follows :

$\begin{array}{1 1}(a)\;X_2,OH^-\;and\; RCOCH_2X\\(b)\;X_2,OH^-\;and\; RCOCX_3\\(c)\;X_2,OH^-\;and \;RCOCHX_2\\(d)\;Only\;X_2\;and\; RCOCX_3\end{array}$

In the haloform reaction the reagent is $X_2$ and $NaOH(OH^-)$ will give $OX^-$
Hence (b) is the correct answer.